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偶今天折騰了好久，搞了個(gè)正反轉(zhuǎn)的程序，竟然不執(zhí)行，求指點(diǎn)
#include <reg52.h>
sbit s4=P3^6;
sbit s5=P3^7;
sbit km1=P1^3;
sbit km2=P1^5;
void main()
{ 
km1=1;
km2=1;
while(1){
if (s4==0)
{
km1=0;
km2=1;
}
if (s5==0){
km1=1;
km2=0;
}  
}
}

有點(diǎn)難度呀，